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Rewrite the expression $\frac{11}{6x^2-7x-3}$ inside the integral in factored form
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$\int\frac{11}{\left(2x-3\right)\left(3x-1\right)}dx$
Learn how to solve problems step by step online. Find the integral int(11/(6x^2-7x+-3))dx. Rewrite the expression \frac{11}{6x^2-7x-3} inside the integral in factored form. Rewrite the fraction \frac{11}{\left(2x-3\right)\left(3x-1\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(2x-3\right)\left(3x-1\right). Multiplying polynomials.