# Step-by-step Solution

## Integral of $36-\left(6-4x+x^2\right)^2$

Go!
1
2
3
4
5
6
7
8
9
0
x
y
(◻)
◻/◻
÷
2

e
π
ln
log
log
lim
d/dx
Dx
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Videos

$24x^2-\frac{1}{5}x^{5}+2x^{4}-\frac{16}{3}x^{3}-4x^{3}+C_0$

## Step-by-step explanation

Problem to solve:

$\int_{ }^{ }\left(36-\left(6-4x+x^2\right)^2\right)dx$
1

The integral of the sum of two or more functions is equal to the sum of their integrals

$\int36dx+\int-\left(6-4x+x^2\right)^2dx$
2

The integral of a constant is equal to the constant times the integral's variable

$36x+\int-\left(6-4x+x^2\right)^2dx$

$24x^2-\frac{1}{5}x^{5}+2x^{4}-\frac{16}{3}x^{3}-4x^{3}+C_0$
$\int_{ }^{ }\left(36-\left(6-4x+x^2\right)^2\right)dx$

Factorization

10. See formulas

~ 1.43 seconds