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# Solve the quadratic equation $x^2+5x+10=60$

## Step-by-step Solution

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### Videos

$x=5,\:x=-10$
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## Step-by-step Solution

Problem to solve:

$x^2+5x+10=60$

Specify the solving method

1

Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$x^2+5x=60-10$

Learn how to solve quadratic equations problems step by step online.

$x^2+5x=60-10$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+5x+10=60. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Subtract the values 60 and -10. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=5 and c=-50. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>.

$x=5,\:x=-10$
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### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$x^2+5x+10=60$