# Step-by-step Solution

## Find the derivative of 1/((x-1)^2)

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$\frac{-2}{\left(x-1\right)^{3}}$

## Step-by-step explanation

Problem to solve:

$\frac{d}{dx}\left(\frac{1}{\left(x-1\right)^2}\right)$
1

Applying the quotient rule which states that if $f(x)$ and $g(x)$ are functions and $h(x)$ is the function defined by ${\displaystyle h(x) = \frac{f(x)}{g(x)}}$, where ${g(x) \neq 0}$, then ${\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}$

$\frac{\left(x-1\right)^2\frac{d}{dx}\left(1\right)-\frac{d}{dx}\left(\left(x-1\right)^2\right)}{\left(\left(x-1\right)^2\right)^2}$
2

The derivative of the constant function is equal to zero

$\frac{0\left(x-1\right)^2-\frac{d}{dx}\left(\left(x-1\right)^2\right)}{\left(\left(x-1\right)^2\right)^2}$

$\frac{-2}{\left(x-1\right)^{3}}$

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$\frac{d}{dx}\left(\frac{1}{\left(x-1\right)^2}\right)$

### Main topic:

Differential calculus

~ 0.53 seconds