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# Integrate the function $\frac{x^2}{110^{-141}}$ from 0 to $\frac{5}{2}$

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##  Final answer to the problem

$\frac{125}{110^{-141}\cdot 24}$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Integrate by partial fractions
• Integrate by substitution
• Integrate by parts
• Integrate using tabular integration
• Integrate by trigonometric substitution
• Weierstrass Substitution
• Integrate using trigonometric identities
• Integrate using basic integrals
• Product of Binomials with Common Term
Can't find a method? Tell us so we can add it.
1

Take the constant $\frac{1}{110^{-141}}$ out of the integral

$\frac{1}{110^{-141}}\int_{0}^{\frac{5}{2}} x^2dx$

Learn how to solve differential calculus problems step by step online.

$\frac{1}{110^{-141}}\int_{0}^{\frac{5}{2}} x^2dx$

Learn how to solve differential calculus problems step by step online. Integrate the function (x^2)/(110^(-141)) from 0 to 5/2. Take the constant \frac{1}{110^{-141}} out of the integral. Apply the power rule for integration, \displaystyle\int x^n dx=\frac{x^{n+1}}{n+1}, where n represents a number or constant function, such as 2. Multiplying fractions \frac{1}{110^{-141}} \times \frac{x^{3}}{3}. Evaluate the definite integral.

##  Final answer to the problem

$\frac{125}{110^{-141}\cdot 24}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.