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The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator
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$f\left(\ln\left(x^5\right)-\ln\left(3x^2+6x+2\right)\right)$
Learn how to solve expanding logarithms problems step by step online. Expand the logarithmic expression fln((x^5)/(3x^2+6x+2)). The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator. Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x). Multiply the single term f by each term of the polynomial \left(5\ln\left(x\right)-\ln\left(3x^2+6x+2\right)\right).