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# Solve the quadratic equation $\frac{4367}{8}x^2-\frac{6433}{10}x+\frac{13907}{125}=0$

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##  Final Answer

$x=0.967904,\:x=0.210571$
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##  Step-by-step Solution 

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Divide $4367$ by $8$

$\frac{4367}{8}x^2-\frac{6433}{10}x+\frac{13907}{125}=0$

Learn how to solve quadratic equations problems step by step online.

$\frac{4367}{8}x^2-\frac{6433}{10}x+\frac{13907}{125}=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 4367/8x^2+-6433/10x13907/125=0. Divide 4367 by 8. Divide -6433 by 10. Divide 13907 by 125. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{4367}{8}, b=-643.3 and c=111.256. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

##  Final Answer

$x=0.967904,\:x=0.210571$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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0
a
b
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f
g
m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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