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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=\frac{4367}{8}$, $b=-\frac{6433}{10}$ and $c=111.256$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{\frac{6433}{10}+\pm 413.409499}{1091.75}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 4367/8x^2-6433/10x13907/125=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{4367}{8}, b=-\frac{6433}{10} and c=111.256. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values \frac{6433}{10} and -413.409499. Add the values \frac{6433}{10} and 413.409499.