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Solve the quadratic equation $6x^2-19x+15=0$

Step-by-step Solution

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Final answer to the problem

$x=\frac{3}{2},\:x=\frac{5}{3}$
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Step-by-step Solution

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  • Find the derivative using the definition
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1

Factor the trinomial $6x^2-19x+15$ of the form $ax^2+bx+c$, first, make the product of $6$ and $15$

$\left(6\right)\left(15\right)=90$

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$\left(6\right)\left(15\right)=90$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 6x^2-19x+15=0. Factor the trinomial 6x^2-19x+15 of the form ax^2+bx+c, first, make the product of 6 and 15. Now, find two numbers that multiplied give us 90 and add up to -19. Rewrite the original expression. Factor 6x^2-10x-9x+15 by the greatest common divisor 3.

Final answer to the problem

$x=\frac{3}{2},\:x=\frac{5}{3}$

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Function Plot

Plotting: $6x^2-19x+15$

SnapXam A2
Answer Assistant

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Got a different answer? Verify it!

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2
3
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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