Final Answer
$x>4.627183$
Got another answer? Verify it here!
Step-by-step Solution
Problem to solve:
$19x^2-140x+241>0$
Specify the solving method
1
Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($19$) to all terms
$19\left(x^2-\frac{140}{19}x+\frac{241}{19}\right)>0$
Learn how to solve inequalities problems step by step online.
$19\left(x^2-\frac{140}{19}x+\frac{241}{19}\right)>0$
Learn how to solve inequalities problems step by step online. Solve the inequality 19x^2-140x+241>0. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (19) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{140}{19}xx+13.573407. Subtract the values \frac{241}{19} and -13.573407.
Final Answer
$x>4.627183$