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# Solve the inequality $19x^2-140x+241>0$

## Step-by-step Solution

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$x>4.627183$
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##  Step-by-step Solution 

Problem to solve:

$19x^2-140x+241>0$

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Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($19$) to all terms

$19\left(x^2-\frac{140}{19}x+\frac{241}{19}\right)>0$

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$19\left(x^2-\frac{140}{19}x+\frac{241}{19}\right)>0$

Learn how to solve inequalities problems step by step online. Solve the inequality 19x^2-140x+241>0. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (19) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{140}{19}xx+13.573407. Subtract the values \frac{241}{19} and -13.573407.

$x>4.627183$

SnapXam A2

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Inequalities

~ 0.33 s

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