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Solve the quadratic equation $-\frac{9}{10}x^2+x+3=0$

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Solution

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Final Answer

$x=2.463952,\:x=-1.35284$
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Step-by-step Solution

Problem to solve:

$-\frac{9}{10}x^2+x+3=0$

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1

For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by $-1$

$\frac{9}{10}x^2-x-3=0$

Learn how to solve quadratic equations problems step by step online.

$\frac{9}{10}x^2-x-3=0$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation -9/10x^2+x+3=0. For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by -1. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{9}{10}, b=-1 and c=-3. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 1 and -3.435113.

Final Answer

$x=2.463952,\:x=-1.35284$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main topic:

Quadratic equations

Used formulas:

1. See formulas

Time to solve it:

~ 0.04 s

Related topics:

Quadratic equationsEquationsQuadratic Formula

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