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For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by $-1$
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$\frac{9}{10}x^2-x-3=0$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation -9/10x^2+x+3=0. For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by -1. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{9}{10}, b=-1 and c=-3. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 1 and -3.435113.