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# Solve the quadratic equation $-\frac{9}{10}x^2+x+3=0$

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##  Final answer to the problem

$x=\frac{5}{9}+\frac{\sqrt{295}}{9},\:x=\frac{5}{9}+\frac{-\sqrt{295}}{9}$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

Multiplying the fraction by $x^2$

$\frac{-9x^2}{10}+x+3=0$

Learn how to solve quadratic equations problems step by step online.

$\frac{-9x^2}{10}+x+3=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation -9/10x^2+x+3=0. Multiplying the fraction by x^2. Combine all terms into a single fraction with 10 as common denominator. Multiply both sides of the equation by 10. For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by -1.

##  Final answer to the problem

$x=\frac{5}{9}+\frac{\sqrt{295}}{9},\:x=\frac{5}{9}+\frac{-\sqrt{295}}{9}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.