Final answer to the problem
$x\leq \sqrt{2129}-40$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
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1
Factor the polynomial $80x+x^2$. Add and subtract $\left(\frac{b}{2}\right)^2$, replacing $b$ by it's value $80$
$x^2+80x+1600-1600\leq 529$
Learn how to solve inequalities problems step by step online.
$x^2+80x+1600-1600\leq 529$
Learn how to solve inequalities problems step by step online. Solve the inequality 80x+x^2<=529. Factor the polynomial 80x+x^2. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 80. Now, we can factor x^2+80x+1600 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Moving the term -1600 to the other side of the inequation with opposite sign. Add the values 529 and 1600.
Final answer to the problem
$x\leq \sqrt{2129}-40$
