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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=2$, $b=-300$ and $c=1450$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{300\pm \sqrt{{\left(-300\right)}^2-4\cdot 2\cdot 1450}}{2\cdot 2}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 1450-300x2x^2=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=-300 and c=1450. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{300\pm \sqrt{{\left(-300\right)}^2-4\cdot 2\cdot 1450}}{2\cdot 2}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 300 and -280.