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# Solve the quadratic equation $\frac{11}{10}t^2- \frac{6}{5}+\frac{3}{10}=0$

## Step-by-step Solution

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###  Videos

$t=0.904534,\:t=-0.904534$
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##  Step-by-step Solution 

Problem to solve:

$\frac{11}{10}t^2- \frac{6}{5}+\frac{3}{10}=0$

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We need to isolate the dependent variable $t$, we can do that by simultaneously subtracting $-\frac{9}{10}$ from both sides of the equation

$\frac{11}{10}t^2-\frac{9}{10}+\frac{9}{10}=0+\frac{9}{10}$

Learn how to solve quadratic equations problems step by step online.

$\frac{11}{10}t^2-\frac{9}{10}+\frac{9}{10}=0+\frac{9}{10}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 11/10t^2-6/5+3/10=0. We need to isolate the dependent variable t, we can do that by simultaneously subtracting -\frac{9}{10} from both sides of the equation. Canceling terms on both sides. Divide both sides of the equation by \frac{11}{10}. Simplifying the quotients.

$t=0.904534,\:t=-0.904534$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for tFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even points

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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

~ 0.06 s

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