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# Solve the quadratic equation $t^2\frac{11}{10}-\frac{6}{5}+\frac{3}{10}=0$

## Step-by-step Solution

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### Videos

$t=0.904534,\:t=-0.904534$
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## Step-by-step Solution

Problem to solve:

$\frac{11}{10} t^2-\frac{6}{5}+\frac{3}{10}=0$

Specify the solving method

1

We need to isolate the dependent variable $t$, we can do that by subtracting $-\frac{9}{10}$ from both sides of the equation

$\frac{11}{10}t^2=\frac{9}{10}$

Learn how to solve quadratic equations problems step by step online.

$\frac{11}{10}t^2=\frac{9}{10}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 11/10t^2-6/5+3/10=0. We need to isolate the dependent variable t, we can do that by subtracting -\frac{9}{10} from both sides of the equation. Divide both sides of the equation by \frac{11}{10}. Removing the variable's exponent. As in the equation we have the sign \pm, this produces two identical equations that differ in the sign of the term \frac{3}{\sqrt{11}}. We write and solve both equations, one taking the positive sign, and the other taking the negative sign.

$t=0.904534,\:t=-0.904534$
SnapXam A2

### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$\frac{11}{10} t^2-\frac{6}{5}+\frac{3}{10}=0$