Integrate the function $\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi }{9}$ from 0 to $3$

Step-by-step Solution

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Final answer to the problem

$3\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}\right)-\frac{\pi }{3}$
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Step-by-step Solution

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Expand the integral $\int_{0}^{3}\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi }{9}\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$\int_{0}^{3}\frac{\pi }{\sqrt{\left(982\right)^{3}}}dx+\int_{0}^{3}-\frac{\pi }{9}dx$

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$\int_{0}^{3}\frac{\pi }{\sqrt{\left(982\right)^{3}}}dx+\int_{0}^{3}-\frac{\pi }{9}dx$

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Learn how to solve classify algebraic expressions problems step by step online. Integrate the function pi/(982^(3/2))-pi/9 from 0 to 3. Expand the integral \int_{0}^{3}\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi }{9}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{3}\frac{\pi }{\sqrt{\left(982\right)^{3}}}dx results in: 3\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}\right). The integral \int_{0}^{3}-\frac{\pi }{9}dx results in: -\frac{\pi }{3}. Gather the results of all integrals.

Final answer to the problem

$3\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}\right)-\frac{\pi }{3}$

Exact Numeric Answer

$-1.046891$

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Function Plot

Plotting: $\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi }{9}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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