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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=15$, $b=-26$ and $c=-57$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{26+\pm 64}{30}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 15x^2-26x-57=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=15, b=-26 and c=-57. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 26 and -64. Add the values 26 and 64.