Final answer to the problem
$x=3,\:x=-\frac{19}{15}$
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1
Factor the trinomial $15x^2-26x-57$ of the form $ax^2+bx+c$, first, make the product of $15$ and $-57$
$\left(15\right)\left(-57\right)=-855$
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$\left(15\right)\left(-57\right)=-855$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 15x^2-26x+-57=0. Factor the trinomial 15x^2-26x-57 of the form ax^2+bx+c, first, make the product of 15 and -57. Now, find two numbers that multiplied give us -855 and add up to -26. Rewrite the original expression. Factor 15x^2-45x+19x-57 by the greatest common divisor 15.
Final answer to the problem
$x=3,\:x=-\frac{19}{15}$