Solve the differential equation $\frac{dy}{dx}+3x\sqrt{x+1}=0$

Step-by-step Solution

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Final answer to the problem

$y=\frac{-6\sqrt{\left(x+1\right)^{5}}}{5}+2\sqrt{\left(x+1\right)^{3}}+C_0$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
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  • Homogeneous Differential Equation
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  • FOIL Method
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We need to isolate the dependent variable $y$, we can do that by simultaneously subtracting $3x\sqrt{x+1}$ from both sides of the equation

$\frac{dy}{dx}=-3x\sqrt{x+1}$

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$\frac{dy}{dx}=-3x\sqrt{x+1}$

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Learn how to solve differential equations problems step by step online. Solve the differential equation dy/dx+3x(x+1)^(1/2)=0. We need to isolate the dependent variable y, we can do that by simultaneously subtracting 3x\sqrt{x+1} from both sides of the equation. Group the terms of the differential equation. Move the terms of the y variable to the left side, and the terms of the x variable to the right side of the equality. Integrate both sides of the differential equation, the left side with respect to y, and the right side with respect to x. Solve the integral \int1dy and replace the result in the differential equation.

Final answer to the problem

$y=\frac{-6\sqrt{\left(x+1\right)^{5}}}{5}+2\sqrt{\left(x+1\right)^{3}}+C_0$

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Function Plot

Plotting: $\frac{dy}{dx}+3x\sqrt{x+1}$

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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