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Expand the logarithmic expression $\log \left(\frac{\left(1+a\right)b^{2n}}{\left(b+1\right)^n}\right)$

Step-by-step Solution

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Final Answer

$\log \left(1+a\right)+2n\log \left(b\right)-n\log \left(b+1\right)$
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Step-by-step Solution

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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$

$\log \left(\left(1+a\right)b^{2n}\right)-\log \left(\left(b+1\right)^n\right)$

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$\log \left(\left(1+a\right)b^{2n}\right)-\log \left(\left(b+1\right)^n\right)$

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Learn how to solve expanding logarithms problems step by step online. Expand the logarithmic expression log((((1+a)*b^(2*n))/((b+1)^n))). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Use the product rule for logarithms: \log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right), where M=1+a and N=b^{2n}. Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x). Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x).

Final Answer

$\log \left(1+a\right)+2n\log \left(b\right)-n\log \left(b+1\right)$

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Plotting: $\log \left(1+a\right)+2n\log \left(b\right)-n\log \left(b+1\right)$

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7
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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Expanding Logarithms

Logarithm expansion consists of applying the properties of logarithms to express a single logarithm in multiple logarithms, usually much simpler.

Used Formulas

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