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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log \left(\left(1+a\right)b^{2n}\right)-\log \left(\left(b+1\right)^n\right)$
Learn how to solve expanding logarithms problems step by step online. Expand the logarithmic expression log((((1+a)*b^(2*n))/((b+1)^n))). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Use the product rule for logarithms: \log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right), where M=1+a and N=b^{2n}. Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x). Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x).