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# Solve the quadratic equation $-x^2+7x-10=0$

## Step-by-step Solution

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tan
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sinh
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asinh
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### Videos

$x=5,\:x=2$
Got another answer? Verify it here

## Step-by-step Solution

Problem to solve:

$-x^2+7x-10=0$

Specify the solving method

1

Factor the trinomial by $-1$ for an easier handling

$-\left(x^2-7x+10\right)=0$
2

Factor the trinomial $-\left(x^2-7x+10\right)$ finding two numbers that multiply to form $10$ and added form $-7$

$\begin{matrix}\left(-2\right)\left(-5\right)=10\\ \left(-2\right)+\left(-5\right)=-7\end{matrix}$
3

Thus

$-\left(x^2-7x+10\right)=0$
4

Factor the trinomial $\left(x^2-7x+10\right)$ finding two numbers that multiply to form $10$ and added form $-7$

$\begin{matrix}\left(-2\right)\left(-5\right)=10\\ \left(-2\right)+\left(-5\right)=-7\end{matrix}$
5

Thus

$-\left(x-2\right)\left(x-5\right)=0$
6

Solve the product $-(x-2)$

$\left(-x+2\right)\left(x-5\right)=0$
7

Break the equation in factors and set each equal to zero, to obtain

$x-5=0,\:-x+2=0$
8

Solve the equation ($1$)

$x-5=0$
9

We need to isolate the dependent variable $x$, we can do that by subtracting $-5$ from both sides of the equation

$x=5$
10

Solve the equation ($2$)

$-x+2=0$
11

We need to isolate the dependent variable $x$, we can do that by subtracting $2$ from both sides of the equation

$-x=-2$
12

Multiply both sides of the equation by $-1$

$x=2$
13

The $2$ solutions of the equation are

$x=5,\:x=2$

$x=5,\:x=2$
SnapXam A2

### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$-x^2+7x-10=0$