Final Answer
$-\frac{958}{3}$
Got another answer? Verify it here!
Step-by-step Solution
Problem to solve:
$\int_{0}^{2}\left(-161+x^2\right)dx$
Specify the solving method
1
Expand the integral $\int_{0}^{2}\left(-161+x^2\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
$\int_{0}^{2}-161dx+\int_{0}^{2} x^2dx$
Learn how to solve problems step by step online.
$\int_{0}^{2}-161dx+\int_{0}^{2} x^2dx$
Learn how to solve problems step by step online. Integrate the function -161+x^2 from 0 to 2. Expand the integral \int_{0}^{2}\left(-161+x^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{2}-161dx results in: -322. The integral \int_{0}^{2} x^2dx results in: \frac{8}{3}. Gather the results of all integrals.
Final Answer
$-\frac{958}{3}$