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# Integrate $\int\left(-181x+6\right)dx$

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##  Final Answer

$-\frac{181}{2}x^2+6x+C_0$
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##  Step-by-step Solution 

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Expand the integral $\int\left(-181x+6\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$\int-181xdx+\int6dx$

Learn how to solve integrals of polynomial functions problems step by step online.

$\int-181xdx+\int6dx$

Learn how to solve integrals of polynomial functions problems step by step online. Integrate int(-181x+6)dx. Expand the integral \int\left(-181x+6\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int-181xdx results in: -\frac{181}{2}x^2. The integral \int6dx results in: 6x. Gather the results of all integrals.

##  Final Answer

$-\frac{181}{2}x^2+6x+C_0$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve integral of (-181x+6)dx using partial fractionsSolve integral of (-181x+6)dx using basic integralsSolve integral of (-181x+6)dx using u-substitutionSolve integral of (-181x+6)dx using integration by partsSolve integral of (-181x+6)dx using trigonometric substitution

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1
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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: Integrals of Polynomial Functions

Integrals of polynomial functions.

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