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Integrate the function $-161x$ from $3$ to $4$

Step-by-step Solution

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Final Answer

$-\frac{1127}{2}$
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Step-by-step Solution

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The integral of a constant times a function is equal to the constant multiplied by the integral of the function

$-161\int_{3}^{4} xdx$

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$-161\int_{3}^{4} xdx$

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Learn how to solve definite integrals problems step by step online. Integrate the function -161x from 3 to 4. The integral of a constant times a function is equal to the constant multiplied by the integral of the function. Applying the power rule for integration, \displaystyle\int x^n dx=\frac{x^{n+1}}{n+1}, where n represents a number or constant function, in this case n=1. Evaluate the definite integral. Simplify the expression inside the integral.

Final Answer

$-\frac{1127}{2}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

1. See formulas

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