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# Solve the quadratic equation $30x^2+13x-10=0$

## Step-by-step Solution

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###  Videos

$x=0.4,\:x=-0.833333$
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##  Step-by-step Solution 

Problem to solve:

$30x^2+13x-10=0$

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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=30$, $b=13$ and $c=-10$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-13\pm \sqrt{13^2-4\cdot 30\cdot -10}}{2\cdot 30}$

Learn how to solve quadratic equations problems step by step online.

$x=\frac{-13\pm \sqrt{13^2-4\cdot 30\cdot -10}}{2\cdot 30}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 30x^2+13x-10=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=30, b=13 and c=-10. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{-13\pm \sqrt{13^2-4\cdot 30\cdot -10}}{2\cdot 30}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 37 and -13.

$x=0.4,\:x=-0.833333$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even points

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e
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log
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lim
d/dx
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sin
cos
tan
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sec
csc

asin
acos
atan
acot
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acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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