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- Integrate by partial fractions
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- Weierstrass Substitution
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- Product of Binomials with Common Term
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Expand the integral $\int_{-2}^{2}\left(x^2-4\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{-2}^{2} x^2dx+\int_{-2}^{2}-4dx$
Learn how to solve definite integrals problems step by step online. Integrate the function x^2-4 from -2 to 2. Expand the integral \int_{-2}^{2}\left(x^2-4\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-2}^{2} x^2dx results in: \frac{8}{3}+\frac{8}{3}. Gather the results of all integrals. Combine fractions with common denominator 3.