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Find the integral $\int\frac{x}{1-x^2}dx$

Step-by-step Solution

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sinh
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asinh
acosh
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Videos

$-\frac{1}{2}\ln\left(x+1\right)-\frac{1}{2}\ln\left(-x+1\right)+C_0$
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Step-by-step Solution

Problem to solve:

$\int\frac{x}{1-x^2}dx$

Specify the solving method

1

Rewrite the expression $\frac{x}{1-x^2}$ inside the integral in factored form

$\int\frac{x}{\left(1+x\right)\left(1-x\right)}dx$

Learn how to solve integrals by partial fraction expansion problems step by step online.

$\int\frac{x}{\left(1+x\right)\left(1-x\right)}dx$

Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int(x/(1-x^2))dx. Rewrite the expression \frac{x}{1-x^2} inside the integral in factored form. Rewrite the fraction \frac{x}{\left(1+x\right)\left(1-x\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(1+x\right)\left(1-x\right). Multiplying polynomials.

$-\frac{1}{2}\ln\left(x+1\right)-\frac{1}{2}\ln\left(-x+1\right)+C_0$
SnapXam A2

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$\int\frac{x}{1-x^2}dx$