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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=289$, $b=-714$ and $c=441$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$y=\frac{714\pm \sqrt{{\left(-714\right)}^2-4\cdot 289\cdot 441}}{2\cdot 289}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 289y^2-714y+441=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=289, b=-714 and c=441. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{714\pm \sqrt{{\left(-714\right)}^2-4\cdot 289\cdot 441}}{2\cdot 289}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Add the values 714 and 0.