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# Solve the quadratic equation $\frac{1}{8}x^2-20x+152=0$

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##  Final answer to the problem

$x=152,\:x=8$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=\frac{1}{8}$, $b=-20$ and $c=152$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{20\pm \sqrt{{\left(-20\right)}^2-4\cdot 152\cdot \left(\frac{1}{8}\right)}}{2\cdot \left(\frac{1}{8}\right)}$

Learn how to solve problems step by step online.

$x=\frac{20\pm \sqrt{{\left(-20\right)}^2-4\cdot 152\cdot \left(\frac{1}{8}\right)}}{2\cdot \left(\frac{1}{8}\right)}$

Learn how to solve problems step by step online. Solve the quadratic equation 1/8x^2-20x+152=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{1}{8}, b=-20 and c=152. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 20 and -18.

##  Final answer to the problem

$x=152,\:x=8$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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0
a
b
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u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch