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Rewrite the fraction $\frac{2x^2-3x-36}{\left(2x-1\right)\left(x^2+9\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{2x^2-3x-36}{\left(2x-1\right)\left(x^2+9\right)}=\frac{A}{2x-1}+\frac{Bx+C}{x^2+9}$
Learn how to solve problems step by step online. Find the integral int((2x^2-3x+-36)/((2x-1)(x^2+9)))dx. Rewrite the fraction \frac{2x^2-3x-36}{\left(2x-1\right)\left(x^2+9\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(2x-1\right)\left(x^2+9\right). Multiplying polynomials. Simplifying.