Final Answer
Step-by-step Solution
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Multiply the single term $\frac{1}{3}$ by each term of the polynomial $\left(x+3\right)$
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$\frac{1}{3}x+1-x\geq \frac{1}{4}\left(x-2\right)+3$
Learn how to solve one-variable linear inequalities problems step by step online. Solve the inequality 1/3(x+3)-x>=1/4(x-2)+3. Multiply the single term \frac{1}{3} by each term of the polynomial \left(x+3\right). Combining like terms \frac{1}{3}x and -x. Multiply the single term \frac{1}{4} by each term of the polynomial \left(x-2\right). Add the values -\frac{1}{2} and 3.