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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=4$, $b=-12$ and $c=-1$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$m=\frac{12\pm \sqrt{{\left(-12\right)}^2-4\cdot 4\cdot -1}}{2\cdot 4}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 4m^2-12m-1=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=4, b=-12 and c=-1. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{12\pm \sqrt{{\left(-12\right)}^2-4\cdot 4\cdot -1}}{2\cdot 4}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 12 and -12.649111.