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# Solve the quadratic equation $3x^2-252x+5675=0$

## Step-by-step Solution

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$x=42+11.298968i,\:x=42-11.298968i$
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## Step-by-step Solution

Problem to solve:

$3x^2-252x+5675=0$

Specify the solving method

1

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=3$, $b=-252$ and $c=5675$. Then substitute the values of the coefficients of the equation in the quadratic formula:

• $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{252+\pm \sqrt{-4596}}{6}$

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$x=\frac{252+\pm \sqrt{-4596}}{6}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 3x^2-252x+5675=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=3, b=-252 and c=5675. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Calculate the power \sqrt{-4596} using complex numbers. Calculate the power \sqrt{-4596} using complex numbers.

$x=42+11.298968i,\:x=42-11.298968i$
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### beta Got another answer? Verify it!

Go!
1
2
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4
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6
7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$3x^2-252x+5675=0$