Final answer to the problem
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- Solve by quadratic formula (general formula)
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Factor the trinomial $8x^2-6x+1$ of the form $ax^2+bx+c$, first, make the product of $8$ and $1$
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$\left(8\right)\left(1\right)=8$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 8x^2-6x+1=0. Factor the trinomial 8x^2-6x+1 of the form ax^2+bx+c, first, make the product of 8 and 1. Now, find two numbers that multiplied give us 8 and add up to -6. Rewrite the original expression. Factor 8x^2-4x-2x+1 by the greatest common divisor 4.