Final Answer
Step-by-step Solution
Problem to solve:
Specify the solving method
To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=11$, $b=14$ and $c=-16$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
Learn how to solve quadratic equations problems step by step online.
$x=\frac{-14+\pm 30}{22}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 11x^2+14x-16=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=11, b=14 and c=-16. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 30 and -14. Subtract the values -14 and -30.