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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=11$, $b=14$ and $c=-16$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-14\pm \sqrt{14^2-4\cdot 11\cdot -16}}{2\cdot 11}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 11x^2+14x-16=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=11, b=14 and c=-16. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{-14\pm \sqrt{14^2-4\cdot 11\cdot -16}}{2\cdot 11}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 30 and -14.