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Integrate the function $\frac{\sin\left(x\right)}{1+\cos\left(x\right)}$ from $\frac{3\pi }{2}$ to $2\pi $

Step-by-step Solution

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Final Answer

$-\ln\left(2\right)$
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Step-by-step Solution

Specify the solving method

1

Simplifying

$\int_{\frac{3\pi}{2}}^{2\pi }\frac{\sin\left(x\right)}{1+\cos\left(x\right)}dx$
2

We can solve the integral $\int_{\frac{3\pi}{2}}^{2\pi }\frac{\sin\left(x\right)}{1+\cos\left(x\right)}dx$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $1+\cos\left(x\right)$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part

$u=1+\cos\left(x\right)$
3

Now, in order to rewrite $dx$ in terms of $du$, we need to find the derivative of $u$. We need to calculate $du$, we can do that by deriving the equation above

$du=-\sin\left(x\right)dx$
4

Isolate $dx$ in the previous equation

$\frac{du}{-\sin\left(x\right)}=dx$
5

Substituting $u$ and $dx$ in the integral and simplify

$-\int_{\frac{3\pi}{2}}^{2\pi }\frac{1}{u}du$
6

The integral of the inverse of the lineal function is given by the following formula, $\displaystyle\int\frac{1}{x}dx=\ln(x)$

$\left[-\ln\left(u\right)\right]_{\frac{3\pi}{2}}^{2\pi }$
7

Replace $u$ with the value that we assigned to it in the beginning: $1+\cos\left(x\right)$

$\left[-\ln\left(1+\cos\left(x\right)\right)\right]_{\frac{3\pi}{2}}^{2\pi }$
8

Evaluate the definite integral

$-\ln\left(1+\cos\left(2\pi \right)\right)-\left(-1\right)\ln\left(1+\cos\left(\frac{3\pi}{2}\right)\right)$
9

Simplify the expression inside the integral

$-\ln\left(2\right)$

Final Answer

$-\ln\left(2\right)$

Exact Numeric Answer

$-0.693147$

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Function Plot

Plotting: $\frac{\sin\left(x\right)}{1+\cos\left(x\right)}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

1. See formulas

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