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# Solve the rational equation $\frac{12-9h^2}{h}=0$

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##  Final answer to the problem

$h=\frac{2}{\sqrt{3}},\:h=\frac{-2}{\sqrt{3}}$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for h
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

Factor the polynomial $12-9h^2$ by it's greatest common factor (GCF): $3$

$\frac{3\left(4-3h^2\right)}{h}=0$

Learn how to solve integrals of rational functions problems step by step online.

$\frac{3\left(4-3h^2\right)}{h}=0$

Learn how to solve integrals of rational functions problems step by step online. Solve the rational equation (12-9h^2)/h=0. Factor the polynomial 12-9h^2 by it's greatest common factor (GCF): 3. Multiply both sides of the equation by h. Solve the product 3\left(4-3h^2\right). We need to isolate the dependent variable h, we can do that by simultaneously subtracting 12 from both sides of the equation.

##  Final answer to the problem

$h=\frac{2}{\sqrt{3}},\:h=\frac{-2}{\sqrt{3}}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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1
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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Integrals of Rational Functions

Integrals of rational functions of the form R(x) = P(x)/Q(x).