Final Answer
$z=11,\:z=-12$
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Step-by-step Solution
Problem to solve:
$z^2+z=132$
Specify the solving method
1
Rewrite the equation
$z^2+z-132=0$
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$z^2+z-132=0$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation z^2+z=132. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=1 and c=-132. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 23 and -1.
Final Answer
$z=11,\:z=-12$