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Moving the term $1$ to the other side of the inequation with opposite sign
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$x^2-5x<0-1$
Learn how to solve problems step by step online. Solve the inequality x^2-5x+1<0. Moving the term 1 to the other side of the inequation with opposite sign. Subtract the values 0 and -1. Factor the polynomial x^2-5x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -5. Now, we can factor x^2+-5x+\frac{25}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2.