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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=19$, $b=3$ and $c=-70$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-3+\pm 73}{38}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 19x^2+3x-70=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=19, b=3 and c=-70. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 73 and -3. Subtract the values -3 and -73.