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Solve the quadratic equation $3x^2+5x-12=0$

Step-by-step Solution

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Final Answer

$x=1.333333,\:x=-3$
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Step-by-step Solution

Problem to solve:

$3x^2+5x-12=0$

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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=3$, $b=5$ and $c=-12$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-5\pm \sqrt{5^2-4\cdot 3\cdot -12}}{2\cdot 3}$

Learn how to solve quadratic equations problems step by step online.

$x=\frac{-5\pm \sqrt{5^2-4\cdot 3\cdot -12}}{2\cdot 3}$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 3x^2+5x-12=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=3, b=5 and c=-12. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{-5\pm \sqrt{5^2-4\cdot 3\cdot -12}}{2\cdot 3}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 13 and -5.

Final Answer

$x=1.333333,\:x=-3$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main topic:

Quadratic equations

Used formulas:

1. See formulas

Time to solve it:

~ 0.03 s

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