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Find the limit of $2x-5=-3$ as $x$ approaches $1$

Step-by-step Solution

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Final Answer

$-3$
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Step-by-step Solution

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Evaluate the limit $\lim_{x\to1}\left(2x-5=-3\right)$ by replacing all occurrences of $x$ by $1$

$2\cdot 1-5=-3$

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$2\cdot 1-5=-3$

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Learn how to solve quadratic equations problems step by step online. Find the limit of 2x-5=-3 as x approaches 1. Evaluate the limit \lim_{x\to1}\left(2x-5=-3\right) by replacing all occurrences of x by 1. Multiply 2 times 1. Subtract the values 2 and -5. So the limit results in.

Final Answer

$-3$

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Limits by Direct SubstitutionLimits by L'Hôpital's ruleLimits by FactoringLimits by Rationalizing

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Plotting: $-3$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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