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# Solve the quadratic equation $\frac{7931}{25}x^2- \left(\frac{237933}{500}\right)x+\frac{15607}{125}=0$

## Step-by-step Solution

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$x=1.161038,\:x=0.338981$
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##  Step-by-step Solution 

Problem to solve:

$\frac{7931}{25}x^2- \left(\frac{237933}{500}\right)x+\frac{15607}{125}=0$

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Divide $7931$ by $25$

$\frac{7931}{25}x^2+\frac{-237933}{500}x+\frac{15607}{125}=0$

Learn how to solve quadratic equations problems step by step online.

$\frac{7931}{25}x^2+\frac{-237933}{500}x+\frac{15607}{125}=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 7931/25x^2-237933/500x15607/125=0. Divide 7931 by 25. Divide -237933 by 500. Divide 15607 by 125. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{7931}{25}, b=-475.866 and c=124.856. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

$x=1.161038,\:x=0.338981$

##  Explore different ways to solve this problem

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asinh
acosh
atanh
acoth
asech
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