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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=\frac{7931}{25}$, $b=-475.866$ and $c=124.856$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{25}{15862} 475.866+\pm 260.789532$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 7931/25x^2-237933/500x15607/125=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{7931}{25}, b=-475.866 and c=124.856. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 475.866 and -260.789532. Add the values 475.866 and 260.789532.