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$\int\frac{1}{\left(s+3\right)\left(s-1\right)}ds+\int\frac{-1}{\left(s+3\right)\left(s-1\right)}ds+2\int\frac{s+1}{\left(s+3\right)\left(s-1\right)}ds$
Learn how to solve problems step by step online. Integrate int(1/((s+3)(s-1))+-1/((s+3)(s-1))(2(s+1))/((s+3)(s-1)))ds. Simplify the expression inside the integral. The integral \int\frac{1}{\left(s+3\right)\left(s-1\right)}ds results in: -\frac{1}{4}\ln\left(s+3\right)+\frac{1}{4}\ln\left(s-1\right). The integral \int\frac{-1}{\left(s+3\right)\left(s-1\right)}ds results in: \frac{1}{4}\ln\left(s+3\right)-\frac{1}{4}\ln\left(s-1\right). Gather the results of all integrals.