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Solve the quadratic equation $\frac{3103}{10}x^2-\frac{53397}{50}x+\frac{63466}{125}=0$

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 Final answer to the problem

$x=2.871891,\:x=0.5697461$
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 Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
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Divide $3103$ by $10$

$310.3x^2-\frac{53397}{50}x+\frac{63466}{125}=0$

Learn how to solve algebraic expressions problems step by step online.

$310.3x^2-\frac{53397}{50}x+\frac{63466}{125}=0$

Learn how to solve algebraic expressions problems step by step online. Solve the quadratic equation 3103/10x^2+-53397/50x63466/125=0. Divide 3103 by 10. Divide -53397 by 50. Divide 63466 by 125. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=310.3, b=1067.94 and c=507.728. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

 Final answer to the problem

$x=2.871891,\:x=0.5697461$

 Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch