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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=\frac{3103}{10}$, $b=1067.94$ and $c=507.728$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{5}{3103} 1067.94+\pm \frac{32146}{45}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 3103/10x^2-53397/50x63466/125=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{3103}{10}, b=1067.94 and c=507.728. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 1067.94 and -\frac{32146}{45}. Add the values 1067.94 and \frac{32146}{45}.