ðŸ‘‰ Try now NerdPal! Our new math app on iOS and Android

# Integrate the function $\frac{1}{x^2}$ from $-2$ to $1$

Go!
Symbolic mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

##  Final answer to the problem

The integral diverges.

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Integrate by partial fractions
• Integrate by substitution
• Integrate by parts
• Integrate using tabular integration
• Integrate by trigonometric substitution
• Weierstrass Substitution
• Integrate using trigonometric identities
• Integrate using basic integrals
• Product of Binomials with Common Term
Can't find a method? Tell us so we can add it.
1

Since the integral $\int_{-2}^{1}\frac{1}{x^2}dx$ has a discontinuity inside the interval, we have to split it in two integrals

$\int_{-2}^{0}\frac{1}{x^2}dx+\int_{0}^{1}\frac{1}{x^2}dx$

Learn how to solve definite integrals problems step by step online.

$\int_{-2}^{0}\frac{1}{x^2}dx+\int_{0}^{1}\frac{1}{x^2}dx$

Learn how to solve definite integrals problems step by step online. Integrate the function 1/(x^2) from -2 to 1. Since the integral \int_{-2}^{1}\frac{1}{x^2}dx has a discontinuity inside the interval, we have to split it in two integrals. The integral \int_{-2}^{0}\frac{1}{x^2}dx results in: \lim_{c\to0}\left(\frac{1}{-c}-\frac{1}{2}\right). The integral \int_{0}^{1}\frac{1}{x^2}dx results in: \lim_{c\to0}\left(-1+\frac{1}{c}\right). Gather the results of all integrals.

##  Final answer to the problem

The integral diverges.

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

###  Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

### 20% discount on online tutoring.

##### Please hold while your payment is being processed.
Create an Account