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Solve the inequality $1414\cdot 20x+x^2\leq 60400$

Step-by-step Solution

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Final Answer

$x\leq 2.135624$
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Step-by-step Solution

Problem to solve:

${1414\cdot20\cdot x+x^2}\leq {60400}$

Specify the solving method

1

Multiply $1414$ times $20$

$28280x+x^2\leq 60400$

Learn how to solve inequalities problems step by step online.

$28280x+x^2\leq 60400$

Unlock the first 2 steps of this solution!

Learn how to solve inequalities problems step by step online. Solve the inequality 1414*20x+x^2<=60400. Multiply 1414 times 20. Factor the polynomial 28280x+x^2. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 28280. Now, we can factor x^2+28280x+199939600 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Moving the term -199939600 to the other side of the inequation with opposite sign.

Final Answer

$x\leq 2.135624$
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Got another answer? Verify it!

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1
2
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Useful tips on how to improve your answer:

${1414\cdot20\cdot x+x^2}\leq {60400}$

Main topic:

Inequalities

Time to solve it:

~ 0.07 s

Related topics:

Inequalities