Final Answer
$x\leq 2.135624$
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Step-by-step Solution
Problem to solve:
${1414\cdot20\cdot x+x^2}\leq {60400}$
Specify the solving method
1
Multiply $1414$ times $20$
$28280x+x^2\leq 60400$
Learn how to solve inequalities problems step by step online.
$28280x+x^2\leq 60400$
Learn how to solve inequalities problems step by step online. Solve the inequality 1414*20x+x^2<=60400. Multiply 1414 times 20. Factor the polynomial 28280x+x^2. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 28280. Now, we can factor x^2+28280x+199939600 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Moving the term -199939600 to the other side of the inequation with opposite sign.
Final Answer
$x\leq 2.135624$