Final answer to the problem
$x\leq \sqrt{60400+14140^2}-14140$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Multiply $1414$ times $20$
$28280x+x^2\leq 60400$
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$28280x+x^2\leq 60400$
Learn how to solve problems step by step online. Solve the inequality 1414*20x+x^2<=60400. Multiply 1414 times 20. Factor the polynomial 28280x+x^2. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 28280. Now, we can factor x^2+28280x+14140^2 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Cancel exponents 2 and 1.
Final answer to the problem
$x\leq \sqrt{60400+14140^2}-14140$
