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# Solve the inequality $1414\cdot 20x+x^2\leq 60400$

## Step-by-step Solution

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$x\leq 2.135624$
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## Step-by-step Solution

Problem to solve:

${1414\cdot20\cdot x+x^2}\leq {60400}$

Specify the solving method

1

Multiply $1414$ times $20$

$28280x+x^2\leq 60400$

Learn how to solve inequalities problems step by step online.

$28280x+x^2\leq 60400$

Learn how to solve inequalities problems step by step online. Solve the inequality 1414*20x+x^2<=60400. Multiply 1414 times 20. Factor the polynomial 28280x+x^2. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 28280. Now, we can factor x^2+28280x+199939600 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Moving the term -199939600 to the other side of the inequation with opposite sign.

$x\leq 2.135624$
SnapXam A2

### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

${1414\cdot20\cdot x+x^2}\leq {60400}$