Final Answer
$x\leq 0.640312i-\frac{3}{10}$
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Step-by-step Solution
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1
Combine $\frac{3-2x}{5}+\frac{1}{3}$ in a single fraction
$-4x+\left(x+1\right)^2-\frac{3}{5}\left(3-2x+\frac{5}{3}\right)\leq -\left(x+1\right)^2$
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$-4x+\left(x+1\right)^2-\frac{3}{5}\left(3-2x+\frac{5}{3}\right)\leq -\left(x+1\right)^2$
Learn how to solve problems step by step online. Solve the inequality -4x+(x+1)^2-3((3-2x)/5+1/3)<=-(x+1)^2. Combine \frac{3-2x}{5}+\frac{1}{3} in a single fraction. Add the values 3 and \frac{5}{3}. Expand \left(x+1\right)^2. Combining like terms -4x and 2x.
Final Answer
$x\leq 0.640312i-\frac{3}{10}$