# Solve the equation (2x-5)(x-3)-3(x-5)=x

## \left(2x-5\right)\left(x-3\right)-3\left(x-5\right)=x

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$2x^2-6x=0$

## Step by step solution

Problem

$\left(2x-5\right)\left(x-3\right)-3\left(x-5\right)=x$
1

Multiply $\left(x+-5\right)$ by $-3$

$\left(x-3\right)\left(2x-5\right)+15-3x=x$
2

Multiplying polynomials $x$ and $2x+-5$

$15-3x+15-6x-5x+2x^2=x$
3

Add the values $15$ and $15$

$-3x-6x-5x+2x^2+30=x$
4

Adding $-6x$ and $-3x$

$-5x+2x^2+30-9x=x$
5

Rewrite the equation

$-x-5x+2x^2=0$
6

Adding $-5x$ and $-1x$

$2x^2-6x=0$

$2x^2-6x=0$

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