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A binomial squared (sum) is equal to the square of the first term, plus the double product of the first by the second, plus the square of the second term. In other words: $(a+b)^2=a^2+2ab+b^2$
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$\lim_{x\to0}\left(\frac{441+42x+x^2-441}{x}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(0)lim(((21+x)^2-441)/x). A binomial squared (sum) is equal to the square of the first term, plus the double product of the first by the second, plus the square of the second term. In other words: (a+b)^2=a^2+2ab+b^2. Subtract the values 441 and -441. If we directly evaluate the limit \lim_{x\to 0}\left(\frac{42x+x^2}{x}\right) as x tends to 0, we can see that it gives us an indeterminate form. We can solve this limit by applying L'H么pital's rule, which consists of calculating the derivative of both the numerator and the denominator separately.