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# Solve the quadratic equation $5x^2+7x+10=\frac{4}{5}$

## Step-by-step Solution

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###  Videos

$x=\frac{-7+\sqrt{135}i}{10},\:x=\frac{-7-\sqrt{135}i}{10}$
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##  Step-by-step Solution 

Problem to solve:

$5x^2+7x+10=\frac{4}{5}$

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Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$5x^2+7x=\frac{4}{5}-10$

Learn how to solve quadratic equations problems step by step online.

$5x^2+7x=\frac{4}{5}-10$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 5x^2+7x+10=4/5. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Subtract the values \frac{4}{5} and -10. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=5, b=7 and c=\frac{46}{5}. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

$x=\frac{-7+\sqrt{135}i}{10},\:x=\frac{-7-\sqrt{135}i}{10}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even points

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◻/◻
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e
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ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

~ 0.18 s

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