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# Solve the quadratic equation $x^2+40x- \frac{321}{50}=0$

## Step-by-step Solution

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$x=\frac{43}{269},\:x=-40.159861$
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##  Step-by-step Solution 

Problem to solve:

$x^2+40x- \frac{321}{50}=0$

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1

Divide $-321$ by $50$

$x^2+40x-\frac{321}{50}=0$

Learn how to solve quadratic equations problems step by step online.

$x^2+40x-\frac{321}{50}=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+40x-321/50=0. Divide -321 by 50. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=40 and c=-\frac{321}{50}. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).

$x=\frac{43}{269},\:x=-40.159861$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even pointsFind the discriminant

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0
a
b
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x
y
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(◻)
+
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◻/◻
/
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2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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