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# Solve the quadratic equation $x^2+40x-\frac{321}{50}=0$

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##  Final answer to the problem

$x=\frac{43}{269},\:x=-40.1598611$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
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Divide $-321$ by $50$

$x^2+40x-6.42=0$

Learn how to solve quadratic equations problems step by step online.

$x^2+40x-6.42=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+40x-321/50=0. Divide -321 by 50. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=40 and c=-6.42. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).

##  Final answer to the problem

$x=\frac{43}{269},\:x=-40.1598611$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.