Final Answer
$x=\frac{43}{269},\:x=-40.159861$
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Step-by-step Solution
Problem to solve:
$x^2+40x- \frac{321}{50}=0$
Specify the solving method
1
Divide $-321$ by $50$
$x^2+40x-\frac{321}{50}=0$
Learn how to solve quadratic equations problems step by step online.
$x^2+40x-\frac{321}{50}=0$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+40x-321/50=0. Divide -321 by 50. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=40 and c=-\frac{321}{50}. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).
Final Answer
$x=\frac{43}{269},\:x=-40.159861$