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3\left(\left(-41\cdot1\right)\cdot\frac{m^{11}}{16} m^2\right)^{\frac{1}{4}}\left(\frac{m^3}{81}\right)^{\frac{1}{4}}

Solve ((m^11)/16m^2*1*-41)^(1/4)((m^3)/81)^(1/4)*3

Answer

$\sqrt[5]{43}m^{4}i$

Step-by-step explanation

Problem

$3\left(\left(-41\cdot1\right)\cdot\frac{m^{11}}{16} m^2\right)^{\frac{1}{4}}\left(\frac{m^3}{81}\right)^{\frac{1}{4}}$
1

Multiply $-41$ times $1$

$3\left(\frac{m^3}{81}\right)^{\left(\frac{1}{4}\right)}\left(-41m^2\frac{m^{11}}{16}\right)^{\left(\frac{1}{4}\right)}$

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Answer

$\sqrt[5]{43}m^{4}i$